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A garden snail moves in a straight line from rest to 1.28 cm s$^{-1}$, with a constant acceleration in 1.8 seconds - AQA - A-Level Maths Mechanics - Question 10 - 2018 - Paper 2

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A garden snail moves in a straight line from rest to 1.28 cm s$^{-1}$, with a constant acceleration in 1.8 seconds. Find the acceleration of the snail. Circle your... show full transcript

Worked Solution & Example Answer:A garden snail moves in a straight line from rest to 1.28 cm s$^{-1}$, with a constant acceleration in 1.8 seconds - AQA - A-Level Maths Mechanics - Question 10 - 2018 - Paper 2

Step 1

Find the initial velocity

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Answer

The snail starts from rest, so the initial velocity, u=0u = 0 cm s1^{-1}.

Step 2

Find the final velocity

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Answer

The final velocity, v=1.28v = 1.28 cm s1^{-1}.

Step 3

Use the formula for acceleration

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Answer

The formula for acceleration is given by:

a=vuta = \frac{v - u}{t}

Substituting the values: a=1.2801.8a = \frac{1.28 - 0}{1.8}

This simplifies to: a=1.281.8a = \frac{1.28}{1.8}

Step 4

Calculate the acceleration

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Answer

Calculating the acceleration gives: a0.7111a \approx 0.7111 cm s2^{-2}, which is approximately 0.710.71 cm s2^{-2}.

Step 5

Convert to m s$^{-2}$

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Answer

To convert to m s2^{-2}, we need to divide by 100:

a0.0071m s2a \approx 0.0071 \, \text{m s}^{-2}

Step 6

Circle your answer

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Answer

The correct answer to circle is 0.0071m s20.0071 \, \text{m s}^{-2}.

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