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James is playing a mathematical game on his computer - AQA - A-Level Maths Pure - Question 17 - 2021 - Paper 3

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James is playing a mathematical game on his computer. The probability that he wins is 0.6. As part of an online tournament, James plays the game 10 times. Let $Y$... show full transcript

Worked Solution & Example Answer:James is playing a mathematical game on his computer - AQA - A-Level Maths Pure - Question 17 - 2021 - Paper 3

Step 1

State two assumptions, in context, for $Y$ to be modelled as $B(10, 0.6)$

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Answer

  1. The number of games played is fixed at 10, meaning James plays exactly 10 games in total.

  2. The outcome of each game is independent, so the probability of winning does not change from one game to the next and remains constant at 0.6.

Step 2

Test a 5% significance level whether James's claim is correct.

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Answer

To test James's claim, we start by defining the hypotheses:

  • Null hypothesis (H0H_0): p=0.6p = 0.6 (the probability of winning has not increased).
  • Alternative hypothesis (H1H_1): p>0.6p > 0.6 (the probability of winning has increased).

Using the binomial distribution, we can calculate:

  1. The probability of winning exactly 12 games out of 15 when p=0.6p = 0.6: P(X=12)=(1512)(0.6)12(0.4)3P(X = 12) = \binom{15}{12} (0.6)^{12} (0.4)^{3} After performing the calculations, we find: P(X12)P(X \geq 12) using normal approximation or binomial tables.

  2. The critical region is determined for a 5% significance level, where we find the critical value such that: P(Xk)<0.05P(X \geq k) < 0.05 for the sample size of 15.

  3. If the calculated P(X12)P(X \geq 12) is greater than the significance level, we fail to reject H0H_0; otherwise, we reject H0H_0 and accept H1H_1.

In conclusion, if P(X12)P(X \geq 12) is not significant, then there is insufficient evidence to suggest that James's claim regarding his probability of winning the game has increased.

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