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In a particular year, the height of a male athlete at the Summer Olympics has a mean 1.78 metres and standard deviation 0.23 metres - AQA - A-Level Maths Pure - Question 18 - 2022 - Paper 3

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In a particular year, the height of a male athlete at the Summer Olympics has a mean 1.78 metres and standard deviation 0.23 metres. The heights of 95% of male athl... show full transcript

Worked Solution & Example Answer:In a particular year, the height of a male athlete at the Summer Olympics has a mean 1.78 metres and standard deviation 0.23 metres - AQA - A-Level Maths Pure - Question 18 - 2022 - Paper 3

Step 1

Comment on whether a normal distribution may be suitable to model the height of a male athlete at the Summer Olympics in this particular year.

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Answer

A normal distribution may be suitable to model the height of male athletes at the Summer Olympics as heights are continuous data and about 95% of heights fall within two standard deviations of the mean. Specifically, the mean height is 1.78 metres and the standard deviation is 0.23 metres. Thus, most heights should lie within the range of approximately 1.32 metres to 2.24 metres, which is consistent with a normal distribution.

Step 2

Find the probability that the height of a randomly selected male athlete is 1.82 metres.

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Answer

To find this probability, we first convert the height to a z-score using the formula:

z=xμσz = \frac{x - \mu}{\sigma}

where x=1.82x = 1.82, μ=1.78\mu = 1.78, and σ=0.23\sigma = 0.23.

Calculating the z-score:

z=1.821.780.230.1739z = \frac{1.82 - 1.78}{0.23} \approx 0.1739

Using standard normal distribution tables, we find that the probability corresponding to this z-score is approximately 0.4320. Thus, the probability that the height is exactly 1.82 metres is the density function value, which can be calculated with:

P(X=1.82)0.4320P(X = 1.82) \approx 0.4320.

Step 3

Find the probability that the height of a randomly selected male athlete is between 1.70 metres and 1.90 metres.

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Answer

To calculate this probability, we find the z-scores for both heights.

For x1=1.70x_1 = 1.70:

z1=1.701.780.230.3478z_1 = \frac{1.70 - 1.78}{0.23} \approx -0.3478

For x2=1.90x_2 = 1.90:

z2=1.901.780.230.5217z_2 = \frac{1.90 - 1.78}{0.23} \approx 0.5217

Using the standard normal distribution table, we find:

  • P(Z<z1)0.3656P(Z < z_1) \approx 0.3656
  • P(Z<z2)0.6968P(Z < z_2) \approx 0.6968

Thus, the probability that the height is between 1.70 and 1.90 metres is:

P(1.70<X<1.90)=P(Z<0.5217)P(Z<0.3478)0.69680.3656=0.3312P(1.70 < X < 1.90) = P(Z < 0.5217) - P(Z < -0.3478) \approx 0.6968 - 0.3656 = 0.3312.

Step 4

Calculate the probability that both of their heights are between 1.70 metres and 1.90 metres.

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Answer

Using the results from part (b)(ii), we found the probability that a randomly selected athlete's height is between 1.70 and 1.90 metres is approximately 0.3312. For two independent events (the heights of two athletes), we multiply the probabilities:

P(AB)=P(A)×P(B)=(0.3312)×(0.3312)0.1093P(A \cap B) = P(A) \times P(B) = (0.3312) \times (0.3312) \approx 0.1093.

Step 5

Use this data to calculate estimates of the mean and standard deviation of the heights of male athletes at the Winter Olympics.

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Answer

The mean height (hˉ\bar{h}) can be calculated as follows:

hˉ=hn=69.240=1.73 metres\bar{h} = \frac{\sum h}{n} = \frac{69.2}{40} = 1.73 \text{ metres}

For the standard deviation (s), use the formula:

s=(hhˉ)2n1s = \sqrt{\frac{\sum (h - \bar{h})^2}{n - 1}}

Substituting the values:

s=2.81390.265 metress = \sqrt{\frac{2.81}{39}} \approx 0.265\text{ metres}.

Step 6

Compare the heights of male athletes at the Summer Olympics and male athletes at the Winter Olympics.

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Answer

From part (c), we determined that the mean height for male athletes at the Winter Olympics is 1.73 metres, compared to the mean height of 1.78 metres at the Summer Olympics. Hence, on average, male athletes at the Summer Olympics are taller than those at the Winter Olympics. Additionally, the standard deviation at the Summer Olympics is 0.23, suggesting that the heights there are more consistent compared to the Winter Olympics, which have a standard deviation of approximately 0.265.

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