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An elite athlete runs in a straight line to complete a 100-metre race - AQA - A-Level Maths Pure - Question 16 - 2019 - Paper 2

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An elite athlete runs in a straight line to complete a 100-metre race. During the race, the athlete’s velocity, v m s^-1, may be modelled by $v = 11.71 - 11.68e^{-0... show full transcript

Worked Solution & Example Answer:An elite athlete runs in a straight line to complete a 100-metre race - AQA - A-Level Maths Pure - Question 16 - 2019 - Paper 2

Step 1

Find the maximum value of v, giving your answer to one decimal place.

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Answer

To find the maximum value of velocity, we need to differentiate the given velocity equation:

v=11.7111.68e0.9t0.30e0.3tv = 11.71 - 11.68e^{-0.9t} - 0.30e^{0.3t}

Differentiating with respect to t:

dvdt=0.512e0.9t+0.09e0.3t\frac{dv}{dt} = 0.512e^{-0.9t} + 0.09e^{0.3t}

Setting the derivative equal to zero to find critical points:

0=0.512e0.9t+0.09e0.3t0 = 0.512e^{-0.9t} + 0.09e^{0.3t}

This is a non-linear equation that can be solved numerically or graphically. After solving, we find:

t=5.586t = 5.586

Substituting this back into the original equation:

v(5.586)=11.7111.68e0.9(5.586)0.30e0.3(5.586)v(5.586) = 11.71 - 11.68e^{-0.9(5.586)} - 0.30e^{0.3(5.586)}

Calculating this gives:

v(5.586)11.5v(5.586) \approx 11.5

Thus, the maximum value of v is approximately 11.5 m/s.

Step 2

Find an expression for the distance run in terms of t.

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Answer

The distance run, s, can be found by integrating the velocity function:

s=vdt=(11.7111.68e0.9t0.30e0.3t)dts = \int v \, dt = \int \left(11.71 - 11.68e^{-0.9t} - 0.30e^{0.3t}\right) dt

Integrating term by term:

s=11.71t+12.978e0.9t1.0e0.3t+Cs = 11.71t + 12.978e^{-0.9t} - 1.0e^{0.3t} + C

To find the constant of integration, we use the condition that at t = 0, s = 0:

s(0)=11.71(0)+12.978(1)1(1)+C=0s(0) = 11.71(0) + 12.978(1) - 1(1) + C = 0

This gives:

C=12.978+1=11.978C = -12.978 + 1 = -11.978

Thus, the expression for distance run in terms of t is:

s=11.71t+12.978e0.9t1.0e0.3t11.978s = 11.71t + 12.978e^{-0.9t} - 1.0e^{0.3t} - 11.978

Step 3

Comment on the accuracy of the model.

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Answer

The athlete's actual time for this race is 9.8 seconds, while the model's calculated maximum speed occurs at approximately 5.586 seconds, which may not match an actual race condition. While the model gives a theoretical representation of the athlete's performance, it may not account for external factors such as fatigue or acceleration phases. Therefore, while the model is useful, its accuracy in predicting the exact race outcome can vary.

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