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In a particular year, the height of a male athlete at the Summer Olympics has a mean 1.78 metres and standard deviation 0.23 metres - AQA - A-Level Maths Pure - Question 18 - 2022 - Paper 3

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Question 18

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In a particular year, the height of a male athlete at the Summer Olympics has a mean 1.78 metres and standard deviation 0.23 metres. The heights of 95% of male athl... show full transcript

Worked Solution & Example Answer:In a particular year, the height of a male athlete at the Summer Olympics has a mean 1.78 metres and standard deviation 0.23 metres - AQA - A-Level Maths Pure - Question 18 - 2022 - Paper 3

Step 1

18 (a) Comment on whether a normal distribution may be suitable to model the height of a male athlete at the Summer Olympics in this particular year.

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Answer

A normal distribution may be suitable for modeling the heights of male athletes at the Summer Olympics because:

  • The heights are continuous data, which aligns with the requirements for a normal distribution.
  • The given data on heights indicates that 95% of male athletes' heights fall within two standard deviations of the mean (1.33 m to 2.22 m). This suggests that the heights spread symmetrically around the mean, reinforcing the potential effectiveness of a normal distribution.

Step 2

18 (b) (i) Find the probability that the height of a randomly selected male athlete is 1.82 metres.

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Answer

To find the probability, we first convert the height to a z-score using the formula: z=xμσz = \frac{x - \mu}{\sigma} Where:

  • xx = 1.82 m
  • μ\mu = 1.78 m
  • σ\sigma = 0.23 m

Calculating: z=1.821.780.23=0.040.230.174z = \frac{1.82 - 1.78}{0.23} = \frac{0.04}{0.23} \approx 0.174

Using the z-table, the probability of a z-score of 0.174 is approximately 0.4320. Hence, the probability of selecting a male athlete with a height of 1.82 m is approximately 0.432.

Step 3

18 (b) (ii) Find the probability that the height of a randomly selected male athlete is between 1.70 metres and 1.90 metres.

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Answer

First, we will calculate the z-scores for both heights:

  • For 1.70 m: z1.70=1.701.780.23=0.080.230.348z_{1.70} = \frac{1.70 - 1.78}{0.23} = \frac{-0.08}{0.23} \approx -0.348
  • For 1.90 m: z1.90=1.901.780.23=0.120.230.522z_{1.90} = \frac{1.90 - 1.78}{0.23} = \frac{0.12}{0.23} \approx 0.522

Using the z-table:

  • The probability for z1.70=0.348z_{1.70} = -0.348 is approximately 0.3643.
  • The probability for z1.90=0.522z_{1.90} = 0.522 is approximately 0.7019.

Thus, the probability that a randomly selected male athlete's height is between 1.70 m and 1.90 m is: P(1.70<x<1.90)=P(z1.90)P(z1.70)0.70190.36430.3376P(1.70 < x < 1.90) = P(z_{1.90}) - P(z_{1.70}) \approx 0.7019 - 0.3643 \approx 0.3376

Step 4

18 (b) (iii) Calculate the probability that both of their heights are between 1.70 metres and 1.90 metres.

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Answer

If the heights of the athletes are independent, the probability that both heights fall within this range is the product of the individual probabilities calculated in part (b) (ii): P(both)=P(1.70<x<1.90)2(0.3376)20.1135P(both) = P(1.70 < x < 1.90)^2 \approx (0.3376)^2 \approx 0.1135

Step 5

18 (c) Use this data to calculate estimates of the mean and standard deviation of the heights of male athletes at the Winter Olympics.

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Answer

Given the data:

  • The total height sum is sumh=69.2\\sum h = 69.2 for n=40n = 40 athletes. Thus, the mean is calculated as: hˉ=69.240=1.73m\bar{h} = \frac{69.2}{40} = 1.73 \, m

For the standard deviation, we use: s=(sum(hhˉ)2)n1s = \sqrt{\frac{(\\sum (h - \bar{h})^2)}{n - 1}} Substituting the values: s=2.81390.265s = \sqrt{\frac{2.81}{39}} \approx 0.265

Step 6

18 (d) Using your answers from part (c), compare the heights of male athletes at the Summer Olympics and male athletes at the Winter Olympics.

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Answer

From our calculations:

  • The mean height of male athletes at the Summer Olympics is 1.78 m, while for the Winter Olympics it is 1.73 m. This indicates that athletes at the Summer Olympics tend to be taller on average.
  • Furthermore, considering the standard deviations, the Summer Olympics have a standard deviation of 0.23 m compared to 0.265 m for the Winter Olympics, indicating that the heights of Summer Olympic athletes are less varied compared to those of their Winter Olympic counterparts.

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