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A curve, C, has equation $y = x^2 - 6x + k$, where $k$ is a constant - AQA - A-Level Maths Pure - Question 4 - 2018 - Paper 2

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A curve, C, has equation $y = x^2 - 6x + k$, where $k$ is a constant. The equation $x^2 - 6x + k = 0$ has two distinct positive roots. 4 (a) Sketch C on the axes b... show full transcript

Worked Solution & Example Answer:A curve, C, has equation $y = x^2 - 6x + k$, where $k$ is a constant - AQA - A-Level Maths Pure - Question 4 - 2018 - Paper 2

Step 1

Find the range of possible values for k.

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Answer

To determine the range of possible values for kk that allows the equation x26x+k=0x^2 - 6x + k = 0 to have two distinct positive roots, we consider two conditions:

  1. Condition for Distinct Roots: The discriminant must be positive. Thus,

    36 - 4k > 0\ k < 9$$
  2. Condition for Positive Roots: The value of kk must also ensure that the roots are positive. The vertex (3,k9)(3, k - 9) indicates that for the roots to be positive (the parabola opens upwards), we must have:

    1. The y-intercept k>0k > 0 (the parabola must cross the y-axis above 0).
    2. Ensuring the parabola intersects the x-axis positively requires the vertex' vertical position to be such that its height keeps the roots in the positive region, specifically:

ightarrow k < 9$$

Therefore, combining both conditions gives:

0<k<90 < k < 9

Thus, the final range of possible values for kk is:

Answer: 0<k<90 < k < 9.

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