6 (a) Find the first two terms, in ascending powers of x, of the binomial expansion of
\(
\left( 1 - \frac{x}{2} \right)^{\frac{1}{2}}
\)
6 (b) Hence, for small values of x, show that
\(
sin(4x) + \sqrt{\cos x} \approx A + Bx + Cx^2
\)
where A, B and C are constants to be found. - AQA - A-Level Maths Pure - Question 6 - 2022 - Paper 1
Question 6
6 (a) Find the first two terms, in ascending powers of x, of the binomial expansion of
\(
\left( 1 - \frac{x}{2} \right)^{\frac{1}{2}}
\)
6 (b) Hence, for small val... show full transcript
Worked Solution & Example Answer:6 (a) Find the first two terms, in ascending powers of x, of the binomial expansion of
\(
\left( 1 - \frac{x}{2} \right)^{\frac{1}{2}}
\)
6 (b) Hence, for small values of x, show that
\(
sin(4x) + \sqrt{\cos x} \approx A + Bx + Cx^2
\)
where A, B and C are constants to be found. - AQA - A-Level Maths Pure - Question 6 - 2022 - Paper 1
Step 1
Find the first two terms, in ascending powers of x, of the binomial expansion of \( \left( 1 - \frac{x}{2} \right)^{\frac{1}{2}} \)
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Answer
To find the first two terms of the binomial expansion of ( \left( 1 - \frac{x}{2} \right)^{\frac{1}{2}} ), we use the binomial theorem:
[
(1 + u)^n = 1 + nu + \frac{n(n-1)}{2!}u^2 + \cdots
]
where ( u = -\frac{x}{2} ) and ( n = \frac{1}{2} ).
First term:
[
1
]
Second term:
[
\frac{1}{2} \left(-\frac{x}{2}\right) = -\frac{x}{4}
]
Thus, the first two terms are:
[
1 - \frac{x}{4}
]
Step 2
Hence, for small values of x, show that \( sin(4x) + \sqrt{\cos x} \approx A + Bx + Cx^2 \)
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Answer
For small values of x, we can use the approximations: