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It takes 15.9 hours for half of the sodium atoms to decay - AQA - A-Level Maths Pure - Question 5 - 2020 - Paper 3

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It takes 15.9 hours for half of the sodium atoms to decay. Determine the number of days required for at least 90% of the number of atoms in the original sample to d... show full transcript

Worked Solution & Example Answer:It takes 15.9 hours for half of the sodium atoms to decay - AQA - A-Level Maths Pure - Question 5 - 2020 - Paper 3

Step 1

Substitutes $t = 15.9$ hours and $N = \frac{N_0}{2}$ in the model to find $k$

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Answer

Using the model, we can substitute the known values into the equation:

N=N0ektN = N_0 e^{-kt}

Substituting:

N02=N0ek(15.9)\frac{N_0}{2} = N_0 e^{-k(15.9)}

Dividing both sides by N0N_0 gives:

12=ek(15.9)\frac{1}{2} = e^{-k(15.9)}

Taking the natural logarithm of both sides:

ln(12)=k(15.9)\ln\left(\frac{1}{2}\right) = -k(15.9)

Solving for kk:

k=ln(12)15.9=0.0436k = -\frac{\ln\left(\frac{1}{2}\right)}{15.9} = 0.0436

Step 2

Substitutes their value of $k$ and $N = 0.1N_0$ in the model to find $t$

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Answer

Next, we want to find the time tt when 90%90\% has decayed. Therefore, we set:

N=0.1N0N = 0.1N_0

Using the model again:

0.1N0=N0ekt0.1N_0 = N_0 e^{-kt}

Dividing by N0N_0:

0.1=ekt0.1 = e^{-kt}

Taking the natural logarithm:

ln(0.1)=kt\ln(0.1) = -kt

Using the value of kk:

t=ln(0.1)0.0436t = -\frac{\ln(0.1)}{0.0436}

Step 3

Solves their equation correctly to find $t$

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Answer

Calculating:

t=2.30260.043652.3 hourst = -\frac{-2.3026}{0.0436} \approx 52.3 \text{ hours}

To convert hours to days:

tdays=52.3242.18 dayst_{days} = \frac{52.3}{24} \approx 2.18 \text{ days}

Rounding appropriately yields:

tdays2.2 dayst_{days} \approx 2.2 \text{ days}

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