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Question 8
A curve has equation y = 2x cos 3x + (3x^2 - 4) sin 3x. 8 (a) Find \( \frac{dy}{dx} \), giving your answer in the form \( m x^2 + n \cos 3x \), where m and n a... show full transcript
Step 1
Answer
To find the derivative ( \frac{dy}{dx} ), we will use the product rule. The given function can be differentiated as follows:
Differentiate the first term:
[ \frac{d}{dx}(2x \cos 3x) = 2 \cos 3x + 2x \frac{d}{dx}(\cos 3x) = 2 \cos 3x - 6x \sin 3x ]
Differentiate the second term:
[ \frac{d}{dx}((3x^2 - 4) \sin 3x) = (3 \cdot 2x) \sin 3x + (3x^2 - 4) \frac{d}{dx}(\sin 3x) = 6x \sin 3x + 3(3x^2 - 4) \cos 3x ]
Combine the derivatives from both terms, we have:
[ \frac{dy}{dx} = (2 \cos 3x - 6x \sin 3x) + (6x \sin 3x + 9x^2 \cos 3x - 12 \cos 3x) ]
Simplifying further:
[ \frac{dy}{dx} = (9x^2 - 10) \cos 3x ]
Thus, we can write it in the required form where ( m = 9 ) and ( n = -10 ).
Step 2
Answer
To find the points of inflection, we need to set the second derivative ( \frac{d^2y}{dx^2} ) equal to zero.
We previously found that:
[ \frac{dy}{dx} = (9x^2 - 10) \cos 3x ]
Thus, differentiating ( \frac{dy}{dx} ):
[ \frac{d^2y}{dx^2} = \frac{d}{dx}((9x^2 - 10) \cos 3x) ]
Using the product rule again:
[ \frac{d^2y}{dx^2} = (18x) \cos 3x + (9x^2 - 10)(-3 \sin 3x) ]
Setting ( \frac{d^2y}{dx^2} = 0 ) gives:
[ 18x \cos 3x - 3(9x^2 - 10) \sin 3x = 0 ]
[ 18x \cos 3x = 3(9x^2 - 10) \sin 3x ]
Dividing both sides by 3:
[ 6x \cos 3x = (9x^2 - 10) \sin 3x ]
[ \cot 3x = \frac{9x^2 - 10}{6x} ]
This shows that the x-coordinates of the points of inflection satisfy the given equation.
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