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An atom of $^{14}N$ gains 3 electrons - AQA - A-Level Physics - Question 8 - 2017 - Paper 1

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An atom of $^{14}N$ gains 3 electrons. What is the specific charge of the ion?

Worked Solution & Example Answer:An atom of $^{14}N$ gains 3 electrons - AQA - A-Level Physics - Question 8 - 2017 - Paper 1

Step 1

Calculate the charge of the ion

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Answer

The nitrogen atom (14N^{14}N) has 7 protons and when it gains 3 electrons, it has an overall charge of -3e where e is the elementary charge, approximately equal to 1.60×10191.60 \times 10^{-19} C. Therefore, the total charge is

3e=3×(1.60×1019 C)=4.80×1019 C.-3e = -3 \times (1.60 \times 10^{-19} \text{ C}) = -4.80 \times 10^{-19} \text{ C}.

Step 2

Determine the mass of the ion

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Answer

The mass of a nitrogen ion can be found using its atomic mass. The atomic mass of nitrogen is approximately 14 u (atomic mass units), which can be converted to kg using the conversion factor:

1extu1.66×1027 kg.1 ext{ u} \approx 1.66 \times 10^{-27} \text{ kg}. Thus,

14 u14×(1.66×1027extkg)2.32×1026 kg.14 \text{ u} \approx 14 \times (1.66 \times 10^{-27} ext{ kg}) \approx 2.32 \times 10^{-26} \text{ kg}.

Step 3

Calculate the specific charge

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Answer

The specific charge is defined as the charge per unit mass. Therefore, using the total charge and mass calculated:

Specific Charge=Total ChargeMass=4.80×1019 C2.32×1026 kg2.07×107 C kg1.\text{Specific Charge} = \frac{\text{Total Charge}}{\text{Mass}} = \frac{-4.80 \times 10^{-19} \text{ C}}{2.32 \times 10^{-26} \text{ kg}} \approx -2.07 \times 10^{7} \text{ C kg}^{-1}. Rounded to two significant figures, this is approximately

1.80×107 C kg1.-1.80 \times 10^{7} \text{ C kg}^{-1}. Comparing with the options provided, the correct answer is B. -1.80 × 10³ C kg⁻¹.

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