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A parallel-plate capacitor is made using a sheet of dielectric material between, and in contact with, two plates - AQA - A-Level Physics - Question 21 - 2020 - Paper 2

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A parallel-plate capacitor is made using a sheet of dielectric material between, and in contact with, two plates. The properties of four sheets of dielectric materia... show full transcript

Worked Solution & Example Answer:A parallel-plate capacitor is made using a sheet of dielectric material between, and in contact with, two plates - AQA - A-Level Physics - Question 21 - 2020 - Paper 2

Step 1

Determine the capacitance formula

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Answer

The capacitance (C) of a parallel-plate capacitor with a dielectric material can be expressed as:

C = rac{ ext{Permittivity} imes A}{d}

where:

  • Permittivity = εrε0\varepsilon_r \cdot \varepsilon_0, with εr\varepsilon_r being the relative permittivity and ε0\varepsilon_0 being the permittivity of free space.
  • A is the area of the plates (assumed constant).
  • d is the thickness of the dielectric material.

Step 2

Calculate the capacitance for each sheet

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Answer

Using the above formula and noting that ε0\varepsilon_0 and A are constants, we focus on relative permittivity divided by thickness:

  • For sheet A: CA=20.40=5C_A = \frac{2}{0.40} = 5
  • For sheet B: CB=30.903.33C_B = \frac{3}{0.90} \approx 3.33
  • For sheet C: CC=41.0=4C_C = \frac{4}{1.0} = 4
  • For sheet D: CD=61.63.75C_D = \frac{6}{1.6} \approx 3.75

Step 3

Compare the results

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To maximize capacitance, we compare the calculated values:

  • A: 5
  • B: 3.33
  • C: 4
  • D: 3.75

Sheet A provides the highest capacitance.

Step 4

Final Answer

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Answer

The sheet that will produce the maximum capacitance is Sheet A.

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