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A Johnson decade counter uses a Johnson counter together with decoding logic - AQA - A-Level Physics - Question 4 - 2021 - Paper 8

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A Johnson decade counter uses a Johnson counter together with decoding logic. This arrangement produces a single logic 1 at a series of outputs Q0–Q9 in a continuous... show full transcript

Worked Solution & Example Answer:A Johnson decade counter uses a Johnson counter together with decoding logic - AQA - A-Level Physics - Question 4 - 2021 - Paper 8

Step 1

Describe one functional difference and one functional similarity between how a Johnson decade counter and a BCD counter output their counts.

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Answer

Functional Difference: A Johnson decade counter outputs a sequence of binary codes, resulting in only one output being high at a time, whereas a BCD counter outputs multiple bits representing a binary number continuously in a 4-bit format.

Functional Similarity: Both counters recycle their outputs to represent the count up to 10, with both resetting when reaching their maximum count of 9.

Step 2

Determine the duty cycle and frequency of the signal.

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Duty Cycle: From the oscilloscope, the time high = 5 div x 50 μs/div = 250 μs The time low = 3 div x 50 μs/div = 150 μs Thus, total period = 250 μs + 150 μs = 400 μs

Duty Cycle = (Time High / Total Period) x 100% = (250 μs / 400 μs) x 100% = 62.5%.

Frequency: Using the frequency formula, f = 1/T, where T = Total Period is 400 μs, f = 1 / (400 x 10^-6) = 2.5 kHz.

Step 3

Determine the frequency of the pulses available at Q0 for each counter.

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Answer

For the BCD counter: The frequency at Q0 = 600 Hz, since only one pulse is produced in 10 clock pulses at Q0.

For the Johnson counter: The frequency at Q0 is calculated as: 600 Hz / 10 = 60 Hz.

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