The Moon orbits the Earth in 27 days - AQA - A-Level Physics - Question 10 - 2022 - Paper 2

Angular speed ($\omega$) can be calculated using the formula:

$\omega = \frac{2\pi}{T}$ where $T$ is the orbital period in seconds.

Now, substituting the orbital period:

$\omega = \frac{2\pi}{2,332,800}$ Calculating this gives:

$\omega \approx 2.7 \times 10^{-6} \text{ rad s}^{-1}$

The calculated angular speed of the Moon is approximately $2.7 \times 10^{-6}$ rad s$^{-1}$, which corresponds to option B.