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Table 1 summarises some information about four stars in the constellation Cassiopeia - AQA - A-Level Physics - Question 2 - 2020 - Paper 4

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Table 1 summarises some information about four stars in the constellation Cassiopeia. Table 1 | Name | Colour | Apparent magnitude | Distance / ly | |---... show full transcript

Worked Solution & Example Answer:Table 1 summarises some information about four stars in the constellation Cassiopeia - AQA - A-Level Physics - Question 2 - 2020 - Paper 4

Step 1

Which star has the highest surface temperature?

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Answer

The star Tsih has the highest surface temperature, as it is blue in color, indicating it emits light at shorter wavelengths compared to the other stars listed.

Step 2

Discuss what information can be found from Figure 1 about the temperature and colour of these stars.

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Answer

Figure 1 illustrates the intensity of light received at Earth from the stars Caph and Schedar against wavelength.

  • Caph has a peak intensity at approximately 450 nm, indicating a hotter temperature which aligns with its white color.
  • Schedar peaks at a longer wavelength (around 600 nm), which corresponds to a slightly cooler orange color.

Using Wien's Law, we can calculate the temperature as: T=bλmaxT = \frac{b}{\lambda_{max}}

Where 'b' is Wien's displacement constant (approximately 2898 µm·K).

  • For Caph: TCaph=28980.4506440KT_{Caph} = \frac{2898}{0.450} \approx 6440 K
  • For Schedar: TSchedar=28980.6004828KT_{Schedar} = \frac{2898}{0.600} \approx 4828 K

Caph is hotter than Schedar, confirming that the blue wavelengths correspond to higher temperatures.

Step 3

State which star in Table 1 is dimmest on the absolute magnitude scale.

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Answer

The dimmest star in the list is Tsih, due to its higher apparent magnitude.

Step 4

Calculate the absolute magnitude of Schedar.

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Answer

To calculate the absolute magnitude, we use the formula: M=m5(log10(d)1)M = m - 5 \cdot (\log_{10}(d) - 1) Where:

  • MM is the absolute magnitude,
  • mm is the apparent magnitude (2.2 for Schedar),
  • dd is the distance in parsecs (converting 228 ly to parsecs gives approximately 69.8 pc): MSchedar=2.25(log10(69.8)1)1.0M_{Schedar} = 2.2 - 5 \cdot (\log_{10}(69.8) - 1) \approx -1.0

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