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Which graph shows the light curve for a typical type 1a supernova? Tick (✓) one box - AQA - A-Level Physics - Question 2 - 2021 - Paper 4

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Which graph shows the light curve for a typical type 1a supernova? Tick (✓) one box. A B C D [1 mark] The Andromeda galaxy is approximately 7.7 ×... show full transcript

Worked Solution & Example Answer:Which graph shows the light curve for a typical type 1a supernova? Tick (✓) one box - AQA - A-Level Physics - Question 2 - 2021 - Paper 4

Step 1

Which graph shows the light curve for a typical type 1a supernova?

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Answer

The correct graph that shows the light curve for a typical type 1a supernova is option D. The typical light curve for a type 1a supernova exhibits a peak absolute magnitude followed by a decline, which is best represented in graph D.

Step 2

Deduce whether a type 1a supernova which occurred in Andromeda can be observed from Earth with the naked eye.

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Answer

To determine if the type 1a supernova in Andromeda can be observed from Earth, we use the distance modulus formula:

mM=5imesextlog(d)5m - M = 5 imes ext{log}(d) - 5

Where mm is the apparent magnitude, MM is the absolute magnitude, and dd is the distance in parsecs.

Given:

  • Distance to Andromeda, d=7.7imes106d = 7.7 imes 10^6 pc
  • Absolute magnitude for a type 1a supernova is typically around Mhickapprox19.3M hickapprox -19.3.

Substituting into the distance modulus formula, we have:

m=19.3+5imesextlog(7.7imes106)+5m = -19.3 + 5 imes ext{log}(7.7 imes 10^6) + 5

Calculating the second term:
5imesextlog(7.7imes106)hickapprox5imes6.886hickapprox34.435 imes ext{log}(7.7 imes 10^6) hickapprox 5 imes 6.886 hickapprox 34.43

Thus,
mhickapprox19.3+34.435=10.13m hickapprox -19.3 + 34.43 - 5 = 10.13

Since the apparent magnitude of the supernova is approximately 10.13, which is brighter than the threshold for visibility to the naked eye (approximately 6), it can be concluded that the type 1a supernova could indeed be observed from Earth without any telescopic aid.

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