Two parallel metal plates separated by a distance d have a potential difference V across them - AQA - A-Level Physics - Question 16 - 2021 - Paper 2
Question 16
Two parallel metal plates separated by a distance d have a potential difference V across them. A particle with charge Q is placed midway between the plates.
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Worked Solution & Example Answer:Two parallel metal plates separated by a distance d have a potential difference V across them - AQA - A-Level Physics - Question 16 - 2021 - Paper 2
Step 1
What is the magnitude of the electrostatic force acting on the particle?
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Answer
To find the electrostatic force acting on a charge in an electric field, we can use the formula:
F=QE
where:
F is the force,
Q is the charge,
E is the electric field strength.
Calculate the Electric Field Strength (E):
For two parallel plates, the electric field is given by:
E=dV
where:
V is the potential difference,
d is the separation between the plates.
Substitute E in the Force Equation:
Substituting for E:
F=Q(dV)
Thus, the expression for the force becomes:
F=dQV
This means the magnitude of the electrostatic force acting on the particle is: rac{QV}{d}.