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Two fixed charges of magnitude +Q and +3Q repel each other with a force F - AQA - A-Level Physics - Question 14 - 2020 - Paper 2

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Two fixed charges of magnitude +Q and +3Q repel each other with a force F. An additional charge of -2Q is given to each charge. What are the magnitude and the direc... show full transcript

Worked Solution & Example Answer:Two fixed charges of magnitude +Q and +3Q repel each other with a force F - AQA - A-Level Physics - Question 14 - 2020 - Paper 2

Step 1

Magnitude of force

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Answer

When a charge of -2Q is added to each of the original charges, we need to analyze the forces between all three charges: +Q, +3Q, and -2Q. The charges +Q and +3Q will still repel each other with a force F. However, both +Q and +3Q will attract the charge -2Q.

To find the resultant force due to these interactions:

  1. The force between +Q and -2Q is given by Coulomb's law: FQ,2Q=kQ(2Q)r2=k2Q2r2F_{Q,-2Q} = k \frac{|Q \cdot (-2Q)|}{r^2} = k \frac{2Q^2}{r^2}

  2. The force between +3Q and -2Q is: F3Q,2Q=k3Q(2Q)r2=k6Q2r2F_{3Q,-2Q} = k \frac{|3Q \cdot (-2Q)|}{r^2} = k \frac{6Q^2}{r^2}

Both forces act in the same direction towards the -2Q charge and will result in a net attractive force towards -2Q.

Step 2

Direction of force

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Answer

The direction of the force between +Q and +3Q is repulsive, while both +Q and +3Q exert an attractive force on -2Q. Thus, despite the original repulsion between +Q and +3Q, the overall interaction with -2Q will lead to an attractive force towards -2Q.

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