A positive charge of 2.0 × 10⁻⁶ C is placed in an electric field at a point where the potential is +500 V - AQA - A-Level Physics - Question 17 - 2020 - Paper 2

The potential energy (U) can be calculated using the formula:

$U = qV$

where:

• $q$ is the charge (2.0 × 10⁻⁶ C)
• $V$ is the electric potential (500 V)

Substituting the values:

$U = (2.0 imes 10^{-6} ext{ C})(500 ext{ V})$

Calculating:

$U = 1.0 imes 10^{-3} ext{ J}$

Thus, the potential energy of the system is 1.0 × 10⁻³ J.