Two gamma photons are produced when a muon and an antimuon annihilate each other - AQA - A-Level Physics - Question 10 - 2018 - Paper 1

The energy of a photon can also be expressed as:

$E = hf$

where $h$ is Planck's constant and $f$ is the frequency of the photon. To find the minimum frequency, we can equate the energy of the photons produced with the energy released during annihilation:

$hf = 2mc^2$

Thus, the frequency is given by:

$f = \frac{2mc^2}{h}$

By substituting the mass of the muon (which is approximately $1.88 \times 10^{-28}$ kg) and known constants, we can calculate the minimum frequency.

After performing the calculations, we find that the minimum frequency of the gamma radiation that could be produced is $5.10 \times 10^{16} Hz$. Therefore, the correct answer is:

Answer B: 5.10 x 10^16 Hz