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A car of mass 580 kg collides with the rear of a stationary van of mass 1200 kg - AQA - A-Level Physics - Question 22 - 2017 - Paper 1

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Question 22

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A car of mass 580 kg collides with the rear of a stationary van of mass 1200 kg. Following the collision, the van moves with a velocity of 6.20 m s⁻¹ and the car re... show full transcript

Worked Solution & Example Answer:A car of mass 580 kg collides with the rear of a stationary van of mass 1200 kg - AQA - A-Level Physics - Question 22 - 2017 - Paper 1

Step 1

Using Conservation of Momentum

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Answer

In an inelastic collision, momentum is conserved. The initial momentum before the collision can be expressed as:

extInitialMomentum=mcarimesvcar+mvanimes0 ext{Initial Momentum} = m_{car} imes v_{car} + m_{van} imes 0

The final momentum after the collision will be:

extFinalMomentum=mcarimes(1.60)+mvanimes6.20 ext{Final Momentum} = m_{car} imes (-1.60) + m_{van} imes 6.20

Given:

  • Mass of car, mcar=580extkgm_{car} = 580 ext{ kg}
  • Mass of van, mvan=1200extkgm_{van} = 1200 ext{ kg}

Setting initial momentum equal to final momentum:

580imesvcar=580imes(1.60)+1200imes6.20580 imes v_{car} = 580 imes (-1.60) + 1200 imes 6.20

Step 2

Solving for the Initial Speed of the Car

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Answer

Substituting the known values into the equation:

  1. Calculate the final momentum:

580imes(1.60)+1200imes6.20=928+7440=6512extkgms1580 imes (-1.60) + 1200 imes 6.20 = -928 + 7440 = 6512 ext{ kg m s}^{-1}

  1. Therefore, the equation becomes:

580imesvcar=6512580 imes v_{car} = 6512

  1. Solving for vcarv_{car}:

vcar=651258011.22extms1v_{car} = \frac{6512}{580} ≈ 11.22 ext{ m s}^{-1}

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