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A satellite X of mass m is in a concentric circular orbit of radius R about a planet of mass M - AQA - A-Level Physics - Question 14 - 2017 - Paper 2

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Question 14

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A satellite X of mass m is in a concentric circular orbit of radius R about a planet of mass M. What is the kinetic energy of X? A GMm 2R B GMm R C 2GMm R D 4GMm R

Worked Solution & Example Answer:A satellite X of mass m is in a concentric circular orbit of radius R about a planet of mass M - AQA - A-Level Physics - Question 14 - 2017 - Paper 2

Step 1

What is the kinetic energy of X?

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Answer

To determine the kinetic energy of the satellite X in a circular orbit, we can start by using the formula for gravitational force and centripetal force.

  1. Gravitational Force: The gravitational force acting on the satellite X is given by:

    Fg=GMmR2F_g = \frac{GMm}{R^2}

    where:

    • GG is the gravitational constant,
    • MM is the mass of the planet,
    • mm is the mass of the satellite, and
    • RR is the radius of the orbit.
  2. Centripetal Force: For the satellite to maintain a circular orbit, the gravitational force must equal the centripetal force required to keep it in orbit:

    Fc=mv2RF_c = \frac{mv^2}{R}

    where:

    • vv is the orbital speed of the satellite.
  3. Equating the Forces:

    Setting the gravitational force equal to the centripetal force:

    GMmR2=mv2R\frac{GMm}{R^2} = \frac{mv^2}{R}

  4. Solving for v:

    Rearranging gives:

    v2=GMRv^2 = \frac{GM}{R}

  5. Kinetic Energy (KE):

    The kinetic energy of the satellite is given by:

    KE=12mv2KE = \frac{1}{2}mv^2

    Substituting the expression for v2v^2:

    KE=12m(GMR)=GMm2RKE = \frac{1}{2}m\left(\frac{GM}{R}\right) = \frac{G Mm}{2R}

Therefore, the kinetic energy of the satellite X is:

Answer:

KE=GMm2RKE = \frac{G Mm}{2R}

Hence, the correct option is A.

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