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Figure 7 shows a system to monitor a tank filling with liquid in which a magnet is mounted on a float - AQA - A-Level Physics - Question 3 - 2019 - Paper 8

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Figure 7 shows a system to monitor a tank filling with liquid in which a magnet is mounted on a float. The Hall effect sensor produces an output voltage $V$. $V$ de... show full transcript

Worked Solution & Example Answer:Figure 7 shows a system to monitor a tank filling with liquid in which a magnet is mounted on a float - AQA - A-Level Physics - Question 3 - 2019 - Paper 8

Step 1

Compare the advantages of the two arrangements for monitoring the movement of the magnet towards the Hall effect sensor.

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Answer

With the north pole facing the sensor:

  • Higher sensitivity and larger gradient over very short range.
  • There is some ambiguity in liquid level due to peak in graph, meaning it may not correctly reference a single output reading.

With the south pole facing the sensor:

  • Less sensitivity and smaller gradient but covers a larger range.
  • There is no ambiguity in liquid level, since each level produces a discrete output up to saturation.

Step 2

Calculate the number of complete revolutions of the drive shaft in one second.

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Answer

From Figure 10, there are approximately 2.4 divisions (5 ms/div) per complete cycle. Thus, for the period TT:

  • Period time = 2.4 divisions × 5 ms/div = 12 ms.

The frequency ff can be found using the formula:

f=1T=112ms=10.012s=83.33Hz.f = \frac{1}{T} = \frac{1}{12 ms} = \frac{1}{0.012 s} = 83.33 Hz.

To find the number of revolutions in one second:

  • Number of revolutions = frequency × time = 83.33Hz×1s=83.3383.33 Hz × 1 s = 83.33 rev.

Rounding down gives 83 full revolutions in one second.

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