An aeroplane flies horizontally at 150 m s⁻¹ along a bearing 60° east of north - AQA - A-Level Physics - Question 22 - 2022 - Paper 1

To find how far north the aeroplane is after one hour, we first need to determine the vertical component of its velocity.

1. Calculate the time: The flight time is 1 hour, which is equivalent to 3600 seconds.

2. Identify speed: The aeroplane flies at a speed of 150 m/s.

3. Determine northward component of velocity: Using the angle of 60°:

   The northward component can be calculated as follows:

   $V_{north} = V imes ext{sin}(60°)$

   Substituting in the values, we get:

   $V_{north} = 150 ext{ m/s} imes ext{sin}(60°) = 150 ext{ m/s} imes \frac{\sqrt{3}}{2} \approx 129.9 ext{ m/s}$

4. Calculate distance traveled north: You can determine how far north the aeroplane travels in one hour:

   $ext{Distance} = V_{north} imes ext{time}$

   $ext{Distance} = 129.9 ext{ m/s} imes 3600 ext{ s} \approx 467640 ext{ m} \approx 470 ext{ km}$

Thus, the correct answer is 470 km (Choice B).