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Immediately after take-off from the surface of the Earth, a rocket of mass 12 000 kg accelerates vertically upwards at 1.4 m s² - AQA - A-Level Physics - Question 22 - 2018 - Paper 1

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Immediately after take-off from the surface of the Earth, a rocket of mass 12 000 kg accelerates vertically upwards at 1.4 m s². What is the thrust produced by the ... show full transcript

Worked Solution & Example Answer:Immediately after take-off from the surface of the Earth, a rocket of mass 12 000 kg accelerates vertically upwards at 1.4 m s² - AQA - A-Level Physics - Question 22 - 2018 - Paper 1

Step 1

Calculate the Weight of the Rocket

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Answer

The weight (W) of the rocket can be calculated using the formula:

W=mgW = mg

Where:

  • m=12,000kgm = 12,000 \, kg (mass of the rocket)
  • g=9.81m/s2g = 9.81 \, m/s^2 (acceleration due to gravity)

Thus:

W=12,000×9.81=117,720NW = 12,000 \times 9.81 = 117,720 \, N

Step 2

Calculate the Net Force Required for Acceleration

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Answer

The net force (F_net) required for the rocket to accelerate can be calculated using Newton's second law:

Fnet=maF_{net} = ma

Where:

  • m=12,000kgm = 12,000 \, kg
  • a=1.4m/s2a = 1.4 \, m/s^2 (upward acceleration)

Thus:

Fnet=12,000×1.4=16,800NF_{net} = 12,000 \times 1.4 = 16,800 \, N

Step 3

Calculate the Total Thrust

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Answer

The total thrust (T) produced by the rocket motor must overcome both the weight and provide the necessary net force for acceleration. Therefore, it can be calculated as follows:

T=W+FnetT = W + F_{net}

Substituting the values obtained:

T=117,720+16,800=134,520NT = 117,720 + 16,800 = 134,520 \, N

This can also be expressed in scientific notation as:

T=1.3×105NT = 1.3 \times 10^5 \, N

Step 4

Select the Correct Answer from the Options

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Answer

Based on the calculated thrust of 1.3×105N1.3 \times 10^5 \, N, the correct answer is C.

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