Photo AI

The Griffith Observatory in Los Angeles includes an astronomical refracting telescope (Griffith telescope) with an objective lens of diameter 305 mm and focal length 5.03 m - AQA - A-Level Physics - Question 1 - 2018 - Paper 4

Question icon

Question 1

The-Griffith-Observatory-in-Los-Angeles-includes-an-astronomical-refracting-telescope-(Griffith-telescope)-with-an-objective-lens-of-diameter-305-mm-and-focal-length-5.03-m-AQA-A-Level Physics-Question 1-2018-Paper 4.png

The Griffith Observatory in Los Angeles includes an astronomical refracting telescope (Griffith telescope) with an objective lens of diameter 305 mm and focal length... show full transcript

Worked Solution & Example Answer:The Griffith Observatory in Los Angeles includes an astronomical refracting telescope (Griffith telescope) with an objective lens of diameter 305 mm and focal length 5.03 m - AQA - A-Level Physics - Question 1 - 2018 - Paper 4

Step 1

Calculate the wavelength of light for which the Griffith telescope has a minimum angular resolution of 1.8 × 10⁻⁴ rad.

96%

114 rated

Answer

To find the wavelength ( ( \lambda )) of light, we can use the formula for angular resolution given by Rayleigh's criterion:

θ=1.22λD\theta = \frac{1.22 \lambda}{D}

Where:

  • ( \theta = 1.8 \times 10^{-4} ) radians
  • ( D = 0.305 ) m (diameter of the lens)

Rearranging the formula to calculate ( \lambda ), we get:

λ=θD1.22\lambda = \frac{\theta D}{1.22}

Substituting the values:

λ=(1.8×104)(0.305)1.22=4.47×105 m\lambda = \frac{(1.8 \times 10^{-4})(0.305)}{1.22} = 4.47 \times 10^{-5} \text{ m}

Thus, the wavelength is approximately 4.47 × 10⁻⁵ m.

Step 2

Calculate the focal length of the eyepiece lens so that an observer can just resolve the two objects when observing them through the Griffith telescope.

99%

104 rated

Answer

Given:

  • Minimum angular resolution of the human eye ( = 3.2 \times 10^{-4} ) rad.
  • Angular resolution required for the telescope's eyepiece should be the same as the human eye.

Using the formula:

M=θtθeM = \frac{\theta_t}{\theta_e}

Where:

  • ( M ) is the magnification
  • ( \theta_t = 1.8 \times 10^{-4} ) rad (angular resolution at the telescope)
  • ( \theta_e ) = 3.2 × 10⁻⁴ rad (angular resolution of human eye)

We find:

M=1.8×1043.2×104=0.5625M = \frac{1.8 \times 10^{-4}}{3.2 \times 10^{-4}} = 0.5625

Next, using the magnification formula related to the focal lengths:

M=ftfeM = \frac{f_t}{f_e}

Where:

  • ( f_t ) is the focal length of the telescope ( f_t = 5.03 ) m
  • ( f_e ) is the focal length of the eyepiece lens

Rearranging gives:

fe=ftM=5.030.56258.95 mf_e = \frac{f_t}{M} = \frac{5.03}{0.5625} \approx 8.95 \text{ m}

So, the focal length of the eyepiece is approximately 8.95 m.

Step 3

Deduce whether this telescope is suitable to obtain a detailed view of Apophis.

96%

101 rated

Answer

Calculation:

First, calculate the angular resolution required to observe Apophis:

Angular resolution=Dd\text{Angular resolution} = \frac{D}{d}

Where:

  • ( D = 325 ) m (diameter of Apophis)
  • ( d = 3.0 \times 10^{6} \text{ km} = 3.0 \times 10^{9} \text{ m} )

Calculating gives:

Angular resolution=3253.0×1091.08×107 radians\text{Angular resolution} = \frac{325}{3.0 \times 10^{9}} \approx 1.08 \times 10^{-7} \text{ radians}

Comparing this with the angular resolution of the telescope:

  • Minimum angular resolution of the telescope ( \approx 1.8 \times 10^{-4} \text{ radians} )
  • Angular resolution required to view Apophis ( \approx 1.08 \times 10^{-7} \text{ radians} )

Since the required resolution (1.08 × 10⁻⁷ rad) is significantly smaller than the angular resolution of the telescope (1.8 × 10⁻⁴ rad), it can be concluded that the Griffith telescope is not suitable for obtaining a detailed view of Apophis.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;