An object of mass 0.15 kg performs simple harmonic motion - AQA - A-Level Physics - Question 30 - 2018 - Paper 1

The maximum kinetic energy (KE) for simple harmonic motion can be calculated using the formula: [ KE_{max} = \frac{1}{2} m \omega^2 A^2 ] where ( m ) is the mass, ( A ) is the amplitude (in meters).

First, convert the amplitude from mm to m: [ A = 55 \text{ mm} = 0.055 , \text{m} ]

Now, plug in the values: [ KE_{max} = \frac{1}{2} (0.15) (5.03^2) (0.055^2) ] [ KE_{max} \approx 0.011 , \text{J} = 11 \times 10^{-3} , \text{J} ] Therefore, the maximum value of the kinetic energy is ( 11 \times 10^{-3} , \text{J} )