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Question 11
Alexei wanted to investigate whether being in day care influenced how much children would share their toys. He used an opportunity sampling technique to recruit chil... show full transcript
Step 1
Answer
Strength: Alexei used an opportunity sample, which allowed him to quickly gather participants for his observation on children sharing toys. This method is efficient, as the children were readily available from families he knew.
Weakness: However, the participants may not be representative of the wider population since they are from a specific area and may share toys differently based on their upbringing or social context. This could affect the validity of his findings.
Step 2
Answer
To calculate the mean, we sum the number of times toys were shared by children in condition A and divide by the number of participants.
Sum = 3 + 6 + 2 + 8 + 4 + 1 = 24
Number of participants = 6
Mean = ( \frac{24}{6} = 4 )
Step 3
Answer
To find the median, we first arrange the number of times toys were shared in condition B in ascending order: 5, 6, 7, 9, 9, 10.
Since there are an even number of data points (6), the median is the average of the 3rd and 4th values.
Median = ( \frac{7 + 9}{2} = 8 )
Step 4
Answer
Alexei calculated an observed value of 4.5 with a critical value of 5 for the Mann-Whitney U test. Since 4.5 is less than the critical value, we conclude that there is a significant difference in sharing toys between the two groups.
Step 5
Answer
Alexei could improve his investigation by using a larger and more diverse sample. For instance, he could observe children in day care and also recruit children from various socioeconomic backgrounds. This would make his sample more representative and potentially yield more generalizable results.
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