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4. Lei investigated the effect of word length on short-term memory capacity - AQA - A-Level Psychology - Question 4 - 2022 - Paper 1

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4. Lei investigated the effect of word length on short-term memory capacity. She used a volunteer sampling technique to gather 20 participants. Lei allocated her par... show full transcript

Worked Solution & Example Answer:4. Lei investigated the effect of word length on short-term memory capacity - AQA - A-Level Psychology - Question 4 - 2022 - Paper 1

Step 1

State the fully operationalised independent variable (IV)

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Answer

The independent variable (IV) in Lei's investigation is the type of words given to participants, specifically whether the words are monosyllabic or polysyllabic.

Step 2

State the fully operationalised dependent variable (DV)

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Answer

The dependent variable (DV) in this investigation is the number of words recalled correctly by participants from the list of 14 words.

Step 3

Complete Table 2 and calculate the Mann-Whitney U

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Answer

To calculate Mann-Whitney U:

  1. Rank the scores from both conditions:
    • Condition A: Monosyllabic Words

      Number of Words RecalledRank
      916.5
      813.5
      916.5
      1019.5
      1019.5
      1120.5
      916.5
      916.5
      Total145.5
    • Condition B: Polysyllabic Words

      Number of Words RecalledRank
      55
      711
      68
      711
      916.5
      1617
      68
      11
      Total64.5
  2. Calculate U values:
    • For Condition A: U_A = R_A - rac{n_A(n_A + 1)}{2} = 145.5 - rac{8(8 + 1)}{2} = 145.5 - 36 = 109.5
    • For Condition B: U_B = R_B - rac{n_B(n_B + 1)}{2} = 64.5 - rac{8(8 + 1)}{2} = 64.5 - 36 = 28.5
  3. Use the smaller U value: U=28.5U = 28.5

Step 4

Determine whether Lei's data were significant

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Answer

Using the calculated U value (28.5), we compare it to the critical value for a one-tailed Mann-Whitney test with 8 participants in each condition. The critical value at p ≤ 0.05 is 27. Since 28.5 is greater than 27, we conclude that Lei's data are not significant at p ≤ 0.05.

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