Photo AI

In 2019, the price of a Ford Endeavour rose from 30m Rupee to 30.9m Rupee - Edexcel - A-Level Business - Question 2 - 2022 - Paper 1

Question icon

Question 2

In-2019,-the-price-of-a-Ford-Endeavour-rose-from-30m-Rupee-to-30.9m-Rupee-Edexcel-A-Level Business-Question 2-2022-Paper 1.png

In 2019, the price of a Ford Endeavour rose from 30m Rupee to 30.9m Rupee. Using this data and the information from Extract D, calculate the percentage change in qua... show full transcript

Worked Solution & Example Answer:In 2019, the price of a Ford Endeavour rose from 30m Rupee to 30.9m Rupee - Edexcel - A-Level Business - Question 2 - 2022 - Paper 1

Step 1

Calculate Percentage Change in Price

96%

114 rated

Answer

The initial price (P1) is 30m Rupee and the final price (P2) is 30.9m Rupee. The percentage change in price can be calculated using the formula:

Percentage Change in Price=(P2P1)P1×100\text{Percentage Change in Price} = \frac{(P2 - P1)}{P1} \times 100

Substituting the values:

Percentage Change in Price=(30.930)30×100=0.930×100=3%\text{Percentage Change in Price} = \frac{(30.9 - 30)}{30} \times 100 = \frac{0.9}{30} \times 100 = 3\%

Step 2

Calculate Percentage Change in Quantity Demanded Using PED

99%

104 rated

Answer

From Extract D, the Price Elasticity of Demand (PED) for Ford is -2.75. Using the formula:

PED=Percentage Change in Quantity DemandedPercentage Change in Price\text{PED} = \frac{\text{Percentage Change in Quantity Demanded}}{\text{Percentage Change in Price}}

We rearrange to find the Percentage Change in Quantity Demanded:

Percentage Change in Quantity Demanded=PED×Percentage Change in Price\text{Percentage Change in Quantity Demanded} = \text{PED} \times \text{Percentage Change in Price}

Substituting the values:

Percentage Change in Quantity Demanded=2.75×3=8.25%\text{Percentage Change in Quantity Demanded} = -2.75 \times 3 = -8.25\%

Thus, the quantity demanded decreases by 8.25%.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;