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Question 4
A ladder AB has mass M and length 6a. The end A of the ladder is on rough horizontal ground. The ladder rests against a fixed smooth horizontal rail at the point C: ... show full transcript
Step 1
Answer
To find the force exerted at point C, we start by taking moments about point A. The equation we can use is: where N is the force exerted by the rail at C, and we have used the length parameters from the problem.
Substituting sin α = \frac{4}{5} into the equation and rearranging, we find: This confirms the required formula for the force at C.
Step 2
Answer
Next, we resolve the forces acting on the ladder both horizontally and vertically. The equations we set up are:
For horizontal forces: For vertical forces: where F is the frictional force and R is the normal reaction force at A.
Using the earlier derived equation for N: So, we can substitute N in terms of friction as:
From these equations, we perform elimination of R and F to express μ:
Carrying out the simplifications leads us to: Thus, the coefficient of friction between the ladder and ground is \mu \approx 0.367.
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