Photo AI

A uniform beam AB has mass 12 kg and length 3 m - Edexcel - A-Level Maths Mechanics - Question 6 - 2005 - Paper 1

Question icon

Question 6

A-uniform-beam-AB-has-mass-12-kg-and-length-3-m-Edexcel-A-Level Maths Mechanics-Question 6-2005-Paper 1.png

A uniform beam AB has mass 12 kg and length 3 m. The beam rests in equilibrium in a horizontal position, resting on two smooth supports. One support is at end A, the... show full transcript

Worked Solution & Example Answer:A uniform beam AB has mass 12 kg and length 3 m - Edexcel - A-Level Maths Mechanics - Question 6 - 2005 - Paper 1

Step 1

Find the reaction on the beam at C.

96%

114 rated

Answer

To find the reaction force at point C, we can use the principles of moments about point A.

Let the reaction at point C be denoted as R. The weight of the beam can be calculated as:

extWeightofbeam=mg=12extkgimes9.81extm/s2=117.72extN ext{Weight of beam} = mg = 12 ext{ kg} imes 9.81 ext{ m/s}^2 = 117.72 ext{ N}

Taking moments about A (considering clockwise moments as positive):

Rimes2extm=117.72extNimes1.5extmR imes 2 ext{ m} = 117.72 ext{ N} imes 1.5 ext{ m}

Solving for R:

R=117.72extNimes1.5extm2extm=88.29extNR = \frac{117.72 ext{ N} imes 1.5 ext{ m}}{2 ext{ m}} = 88.29 ext{ N}

Thus, the reaction on the beam at C is approximately 88.3 N.

Step 2

Find the distance AD.

99%

104 rated

Answer

For the second part of the question, when the woman stands at point D, the total reaction at C (denote as S) and the reaction at A (denote as R) are equal:

S=R=88.29extNS = R = 88.29 ext{ N}

Considering the total downward forces:

Simes2=48extkgimes9.81extm/s2+12extkgimes9.81extm/s2S imes 2 = 48 ext{ kg} imes 9.81 ext{ m/s}^2 + 12 ext{ kg} imes 9.81 ext{ m/s}^2

Calculating the total weight:

48extkgimes9.81extm/s2+12extkgimes9.81extm/s2=588.6extN48 ext{ kg} imes 9.81 ext{ m/s}^2 + 12 ext{ kg} imes 9.81 ext{ m/s}^2 = 588.6 ext{ N}

Setting up the equation:

2S=588.6extN2S = 588.6 ext{ N}

So:

S=588.62=294.3extNS = \frac{588.6}{2} = 294.3 ext{ N}

Next, we need to find the position of D such that the moments balance:

Simesx=Weightimes32S imes x = Weight imes \frac{3}{2}

Substituting S:

294.3imesx=117.72imes1.5294.3 imes x = 117.72 imes 1.5

We can solve for x:

x=117.72imes1.5294.30.6extmx = \frac{117.72 imes 1.5}{294.3} \approx 0.6 ext{ m}

Thus, the distance AD is approximately 0.6 m.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;