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Three forces, (15i + j) N, (5qi - pj) N and (-3pi - qj) N, where p and q are constants, act on a particle - Edexcel - A-Level Maths Mechanics - Question 1 - 2017 - Paper 1

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Question 1

Three-forces,--(15i-+-j)-N,--(5qi---pj)-N-and--(-3pi---qj)-N,-where-p-and-q-are-constants,-act-on-a-particle-Edexcel-A-Level Maths Mechanics-Question 1-2017-Paper 1.png

Three forces, (15i + j) N, (5qi - pj) N and (-3pi - qj) N, where p and q are constants, act on a particle. Given that the particle is in equilibrium, find the val... show full transcript

Worked Solution & Example Answer:Three forces, (15i + j) N, (5qi - pj) N and (-3pi - qj) N, where p and q are constants, act on a particle - Edexcel - A-Level Maths Mechanics - Question 1 - 2017 - Paper 1

Step 1

Equate the sum of the i components to zero

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Answer

The equation for the i components is given by: 15+5q3p=015 + 5q - 3p = 0 This simplifies to: 5q3p=155q - 3p = -15

Step 2

Equate the sum of the j components to zero

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Answer

The equation for the j components is given by: 1pq=01 - p - q = 0 This can be rearranged to: p+q=1p + q = 1

Step 3

Solve the system of equations

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Answer

We now have the following two equations to solve:

  1. 5q3p=155q - 3p = -15
  2. p+q=1p + q = 1

Substituting equation 2 into equation 1, we find: 5(1p)3p=155(1 - p) - 3p = -15 This simplifies to: 55p3p=155 - 5p - 3p = -15 8p=20-8p = -20 Thus, p=2.5p = 2.5

Substituting the value of p back into equation 2: 2.5+q=12.5 + q = 1 Solving this yields: q=12.5=1.5q = 1 - 2.5 = -1.5

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