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A car is moving along a straight horizontal road - Edexcel - A-Level Maths Mechanics - Question 4 - 2008 - Paper 1

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A car is moving along a straight horizontal road. The speed of the car as it passes the point A is 25 m s⁻¹ and the car maintains this speed for 30 s. The car then d... show full transcript

Worked Solution & Example Answer:A car is moving along a straight horizontal road - Edexcel - A-Level Maths Mechanics - Question 4 - 2008 - Paper 1

Step 1

Sketch, in the space below, a speed-time graph to show the motion of the car from A to B.

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Answer

To sketch the speed-time graph:

  1. Mark the vertical axis as speed (m s⁻¹) and the horizontal axis as time (s).
  2. Plot the initial point A: at time 0 s, speed = 25 m s⁻¹.
  3. Draw a horizontal line from 0 s to 30 s, maintaining the speed of 25 m s⁻¹.
  4. At 30 s, the car begins to decelerate uniformly to 10 m s⁻¹ over an unspecified time period. Assume it takes 8 seconds to reach the new speed (calculated in part b).
  5. Draw a straight line decreasing from 25 m s⁻¹ at 30 s to 10 m s⁻¹ at 38 s.
  6. After 38 s, draw a horizontal line from 38 s to 90 s, showing a constant speed of 10 m s⁻¹.

Step 2

Calculate the deceleration of the car as it decelerates from 25 m s⁻¹ to 10 m s⁻¹.

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Answer

To calculate the deceleration:

  1. Initial speed, u=25u = 25 m s⁻¹, final speed, v=10v = 10 m s⁻¹.
  2. The time taken to decelerate, t=8t = 8 s (from the time calculated in the graph sketch).
  3. Use the formula for deceleration: a=vuta = \frac{v - u}{t}
  4. Substituting the values: a=10258=158=1.875m s2a = \frac{10 - 25}{8} = \frac{-15}{8} = -1.875 \, \text{m s}^{-2}.
  5. Therefore, the deceleration of the car is 1.875 m s⁻².

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