Photo AI

A uniform rod AB has length 1.5 m and mass 8 kg - Edexcel - A-Level Maths Mechanics - Question 3 - 2007 - Paper 1

Question icon

Question 3

A-uniform-rod-AB-has-length-1.5-m-and-mass-8-kg-Edexcel-A-Level Maths Mechanics-Question 3-2007-Paper 1.png

A uniform rod AB has length 1.5 m and mass 8 kg. A particle of mass m kg is attached to the rod at B. The rod is supported at the point C, where AC = 0.9 m, and the ... show full transcript

Worked Solution & Example Answer:A uniform rod AB has length 1.5 m and mass 8 kg - Edexcel - A-Level Maths Mechanics - Question 3 - 2007 - Paper 1

Step 1

Show that m = 2.

96%

114 rated

Answer

To prove that m=2m = 2, we start by analyzing the torque about point C. The rod's weight acts at its center of mass, which is at 0.75 m from A. Thus, the torque due to the rod is:

extTorqueextrod=8gimes(0.90.75)=8gimes0.15 ext{Torque}_{ ext{rod}} = 8g imes (0.9 - 0.75) = 8g imes 0.15

For the particle at B, the torque is given by:

extTorqueextparticle=mgimes(1.50.9)=mgimes0.6 ext{Torque}_{ ext{particle}} = mg imes (1.5 - 0.9) = mg imes 0.6

Setting the counterclockwise torque equal to the clockwise torque for equilibrium, we have:

8gimes0.15=mgimes0.68g imes 0.15 = mg imes 0.6

Simplifying, we find:

1.2=0.6m1.2 = 0.6m

Solving for m gives:

m = rac{1.2}{0.6} = 2.

Step 2

Find the distance AD.

99%

104 rated

Answer

To find the distance AD, we need to set up the moments around point D.

Let the distance between point A and D be xx. Then, the distance from D to B is (1.5x)(1.5 - x).

The moment about point D will be:

M(D):5gimesx=8gimes(0.75x)+2gimes(1.5x)M(D) : 5g imes x = 8g imes (0.75 - x) + 2g imes (1.5 - x)

Substituting the known values:

5gimesx=8gimes(0.75x)+2gimes(1.5x)5g imes x = 8g imes (0.75 - x) + 2g imes (1.5 - x)

After canceling out gg, we get:

5x=8(0.75x)+2(1.5x)5x = 8(0.75 - x) + 2(1.5 - x)

Expanding and rearranging gives:

5x=6+0.5x5x = 6 + 0.5x

This simplifies to:

5x0.5x=65x - 0.5x = 6

Thus,

4.5x = 6 \\ x = rac{6}{4.5} = rac{4}{3} = 0.6 ext{ m}.

Therefore, the distance AD is:

AD=x=0.6extm.AD = x = 0.6 ext{ m}.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;