A uniform rod AB has length 3 m and weight 120 N - Edexcel - A-Level Maths Mechanics - Question 6 - 2003 - Paper 1
Question 6
A uniform rod AB has length 3 m and weight 120 N. The rod rests in equilibrium in a horizontal position, smoothly supported at points C and D, where AC = 0.5 m and A... show full transcript
Worked Solution & Example Answer:A uniform rod AB has length 3 m and weight 120 N - Edexcel - A-Level Maths Mechanics - Question 6 - 2003 - Paper 1
Step 1
Show that $W = \frac{60}{1 - x}$
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Answer
To establish the relationship between W, the weight of the particle, and x, we can apply the principle of moments around point D:
Setting Up the Equation: The moments about point D should balance since the rod is in equilibrium. Thus,
W×(2−x)+120×1.5=R×3
Here, R represents the reaction force at point C.
Expressing R: From the equilibrium of forces vertically:
R=3W+120
Substituting into Moment Equation: Substitute R into the moment equation:
W(2−x)+120×1.5=(3W+120)×3
Expanding and Simplifying: This leads to:
W(2−x)+180=9W+360
Rearranging gives:
W(2−x)−9W+180−360=0
Which simplifies to:
W(1−x)=60
Final Results: Thus,
W=1−x60.
Step 2
Hence deduce the range of possible values of x
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Answer
From the equation we derived:
W=1−x60,
We can identify the conditions for W to be valid:
Condition for W: For W to be positive, we need:
1−x>0⟹x<1.
Minimum Value of W: Also, W must be greater than zero, requiring:
1−x>0⟹x<1,
and we cannot have x reaching or exceeding 1.
Thus, the only condition left is ensuring that W is positive:
W>0⟹0<x<1.
Conclusion: Hence, the range of possible values of x is: