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Question 5
The lifetime, L, hours, of a battery has a normal distribution with mean 18 hours and standard deviation 4 hours. Alice's calculator requires 4 batteries and will s... show full transcript
Step 1
Answer
To find the probability that a battery lasts longer than 16 hours under a normal distribution, we first need to standardize the value using the Z-score formula:
where:
Substituting the values:
Using the standard normal distribution table, we find the probability corresponding to . This gives us:
Thus, the probability that a battery lasts longer than 16 hours is:
Step 2
Answer
After using the calculator for 16 hours, Alice has 4 hours left of exams. We first need the likelihood that at least one of the 4 batteries will last more than 20 hours (16 used + 4 remaining).
Using the previously calculated probability of a battery lasting longer than 20 hours:
Finding the corresponding probability for :
The probability of a battery lasting less than 20 hours is:
Thus, the probability that all 4 batteries last more than 20 hours is:
Step 3
Answer
With 2 new batteries added in, the overall probability can be evaluated by focusing on the chances of at least one battery still working:
Given the previous computation, we denote the probability that her calculator does stop working (i.e., all batteries fail) as:
Then using the complementary probability:
Step 4
Answer
The hypotheses for the test regarding the battery lifetime are:
Using the sample mean(\bar{x} = 19.2), sample size , standard deviation . We utilize:
Substituting in:
This Z-score can be checked against Z-tables to determine if it falls within the critical region for . The critical value corresponding to a one-tailed test of 5% significance is approximately 1.645. Since , we fail to reject the null hypothesis, suggesting that Alice's belief does not hold up at the desired level of significance.
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