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Particle P has mass 3 kg and particle Q has mass 2 kg - Edexcel - A-Level Maths Mechanics - Question 2 - 2011 - Paper 1

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Particle P has mass 3 kg and particle Q has mass 2 kg. The particles are moving in opposite directions on a smooth horizontal plane when they collide directly. Immed... show full transcript

Worked Solution & Example Answer:Particle P has mass 3 kg and particle Q has mass 2 kg - Edexcel - A-Level Maths Mechanics - Question 2 - 2011 - Paper 1

Step 1

Find the speed of each particle after the collision.

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Answer

Let the speed of particle P after the collision be denoted as vv (m/s). Then the speed of particle Q after the collision is v1v - 1 (m/s) since the difference in their speeds is 1 m/s.

Using the principle of conservation of linear momentum:

33+2(2)=3v+2(v1)3 \cdot 3 + 2 \cdot (-2) = 3v + 2(v - 1)

This gives: 94=3v+2v29 - 4 = 3v + 2v - 2
5=5v25 = 5v - 2
5+2=5v5 + 2 = 5v
7=5v7 = 5v
v=1.4m/sv = 1.4\, \text{m/s}

Thus, particle P has speed 1.4m/s1.4\, \text{m/s} after the collision and particle Q has speed 0.4m/s0.4\, \text{m/s} after the collision.

Step 2

Find the magnitude of the impulse exerted on P by Q.

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Answer

Impulse is given by the change in momentum, which can be expressed as:

J=m(vfvi)J = m(v_f - v_i)

Where:

  • mm is the mass of the particle (here, particle P has mass 3 kg).
  • vfv_f is the final velocity of particle P (1.4m/s1.4\, \text{m/s}).
  • viv_i is the initial velocity of particle P (3m/s3\, \text{m/s}).

Therefore, the impulse exerted on particle P by particle Q is:

J=3(1.43)=3(1.6)=4.8NsJ = 3(1.4 - 3) = 3 \cdot (-1.6) = -4.8\, \text{Ns}

The magnitude is: J=4.8Ns|J| = 4.8\, \text{Ns}

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