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Question 2
A small stone A of mass 3m is attached to one end of a string. A small stone B of mass m is attached to the other end of the string. Initially A is held at rest on a... show full transcript
Step 1
Answer
To derive the equation of motion for stone A, we can consider the forces acting on it. The forces include:
The gravitational force along the plane:
F_g = 3mg imes rac{3}{5}
where the 3 in the numerator represents mass A (3m) and the angle of incline is given by the tangent function.
The frictional force opposing the motion:
F_f = rac{1}{6} R
where R is the normal reaction force, defined as:
R = 3mg imes rac{4}{5}
using the cosine of angle α to resolve it perpendicular to the plane.
The equation of motion can be expressed as:
3mg imes rac{3}{5} - F_f - T = 3ma
Thus, the equation becomes:
3mg imes rac{3}{5} - rac{1}{6} R - T = 3ma.
Step 2
Answer
First, we know from the previous part the equation:
3mg imes rac{3}{5} - \frac{1}{6} R - T = 3ma
Next, substituting the value of R:
When substituted, we derive:
Resolving the equation further yields:
Thus on simplifying:
Therefore, the acceleration a can be expressed in terms of g as:
$$a = \frac{1}{10}g.$
Step 3
Answer
The motion of stone B can be visualized on a velocity-time graph of the form:
In conclusion, the velocity-time graph will be a straight line for the motion of B, depicting continuous acceleration.
Step 4
Answer
The working of part (b) would be affected as follows:
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