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A particle of weight 8 N is attached at C to the ends of two light inextensible strings AC and BC - Edexcel - A-Level Maths Mechanics - Question 2 - 2013 - Paper 1

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A particle of weight 8 N is attached at C to the ends of two light inextensible strings AC and BC. The other ends, A and B, are attached to a fixed horizontal ceilin... show full transcript

Worked Solution & Example Answer:A particle of weight 8 N is attached at C to the ends of two light inextensible strings AC and BC - Edexcel - A-Level Maths Mechanics - Question 2 - 2013 - Paper 1

Step 1

(i) the tension in the string AC

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Answer

To find the tension in string AC, denoted as TACT_{AC}, we can resolve the forces acting on the particle in both the horizontal and vertical directions.

  1. Vertical Forces: The weight of the particle (8 N) acts downward, and the vertical component of the tension TACT_{AC} acts upward. Thus, we have: T_{AC} imes rac{1}{ ext{sin}(35°)} - 8 = 0 Rearranging this gives us: TACimesextsin(35°)=8T_{AC} imes ext{sin}(35°) = 8

  2. Calculating TACT_{AC}: T_{AC} = rac{8}{ ext{sin}(35°)} Using a calculator, we find:

ightarrow T_{AC} ext{ (approximately)} = 13.95 ext{ N}$$

Step 2

(ii) the tension in the string BC

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Answer

To find the tension in string BC, denoted as TBCT_{BC}, we will also resolve the forces acting on the particle:

  1. Vertical Forces: The vertical component of TBCT_{BC} must also counteract the weight of the particle. Thus, we have: TBCimesextsin(25°)=8T_{BC} imes ext{sin}(25°) = 8

  2. Calculating TBCT_{BC}: T_{BC} = rac{8}{ ext{sin}(25°)} By calculating this, we find:

ightarrow T_{BC} ext{ (approximately)} = 18.92 ext{ N}$$

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