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A car moves along a horizontal straight road, passing two points A and B - Edexcel - A-Level Maths Mechanics - Question 3 - 2008 - Paper 1

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A car moves along a horizontal straight road, passing two points A and B. At A the speed of the car is 15 m s⁻¹. When the driver passes A, he sees a warning sign W a... show full transcript

Worked Solution & Example Answer:A car moves along a horizontal straight road, passing two points A and B - Edexcel - A-Level Maths Mechanics - Question 3 - 2008 - Paper 1

Step 1

Sketch, in the space below, a speed-time graph to illustrate the motion of the car as it moves from A to B.

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Answer

To sketch the speed-time graph:

  1. Start at point A (0s, 15 m/s).
  2. Show a rapid decrease to 5 m/s at time T = 12s (point W).
  3. From T = 12s to T = 16s, illustrate constant speed at 5 m/s.
  4. From T = 16s to T = 22s, show the increase in speed from 5 m/s to V m/s with a uniform acceleration slope.
  5. Maintain the constant speed at V from T = 22s onwards.

Step 2

Find the time taken for the car to move from A to B.

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Answer

To find the total time:

  1. Time from A to W (deceleration) = 12s.
  2. Time from W to the point of acceleration = 16s.
  3. Time from the acceleration point to B = 22s.

Total time, T = 12 + 16 + 22 = 50s.

Step 3

The distance from A to B is 1 km.

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Answer

Use the formula for distance:

Let the constant speed be V. The distance covered is given by:

egin{align*} ext{Distance} & = ext{Distance from A to W} + ext{Distance from W to V} + ext{Distance from V to B}
& = 120 + rac{1}{2}(15 + 5)(12) + V(22) = 1000 ext{ m}
ext{Solving gives: } & rac{1}{2}(15 + 5)(12) = 120 ext{ m},
30 + 11V = 1000 ext{ m}
ext{So, } V & = 28 ext{ m/s}. ext{Then the value of V is: } \ V = 28.

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