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[In this question, the unit vectors i and j are due east and due north respectively - Edexcel - A-Level Maths Mechanics - Question 7 - 2012 - Paper 1

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[In this question, the unit vectors i and j are due east and due north respectively. Position vectors are relative to a fixed origin O.] A boat P is moving with con... show full transcript

Worked Solution & Example Answer:[In this question, the unit vectors i and j are due east and due north respectively - Edexcel - A-Level Maths Mechanics - Question 7 - 2012 - Paper 1

Step 1

Calculate the speed of P.

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Answer

To find the speed of the boat P, we use the formula for speed, which is the magnitude of velocity:

ormalsize egin{pmatrix} -4 \ 8 \\ ext{km h}^{-1} \end{pmatrix} = \\ ormalsize ext{speed} = \\ ormalsize rac{(4^2 + 8^2)^{1/2}}{1} \\ ext{= } rac{ ormalsize (16 + 64)^{1/2}}{1} = rac{ ormalsize (80)^{1/2}}{1} \\ = 8.944 ext{ km h}^{-1} ext{ (approximately 8.9 km h}^{-1}).

Step 2

Write down p in terms of t.

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Answer

The position vector p of boat P at time t is given by:

p=(2i8j)+t(4i+8j)=(24t)i+(8+8t)jp = (2i - 8j) + t(-4i + 8j) = (2 - 4t)i + (-8 + 8t)j

Step 3

the value of t when P is due west of Q.

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Answer

To find when boat P is due west of boat Q, we equate the j-components of their position vectors:

For Q: q=(18i+12j)(6i+8j)q = (18i + 12j) - (6i + 8j), thus: q=(12i+4j)q = (12i + 4j)

For P when due west: The j-component is the same, set: 8+8t=12-8 + 8t = 12 This leads to: 8t = 20 \\ t = rac{20}{8} = rac{5}{2} = 2.5 ext{ hours}

Step 4

the distance between P and Q when P is due west of Q.

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Answer

First, we calculate the position vectors of P and Q at t = 2.5:

For P: p=(24(2.5))i+(8+8(2.5))j=(8)i+(12)jp = (2 - 4(2.5))i + (-8 + 8(2.5))j = (-8)i + (12)j

For Q: q=(12i+4j)q = (12i + 4j)

Now, the distance between P and Q is given by the vector difference: Distance = pq||p - q||:

pq=[(8)12]i+[124]j=(20)i+(8)jp - q = [(-8) - 12]i + [12 - 4]j = (-20)i + (8)j

Then, find the magnitude:

ormalsize egin{pmatrix} -20 \ 8 \\ ext{km} \end{pmatrix} = ormalsize rac{(-20^2 + 8^2)^{1/2}}{1} = ormalsize rac{(400 + 64)^{1/2}}{1} = rac{(464)^{1/2}}{1} ext{ km} \\ = 21.54 ext{ km approximately.}$$

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