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7. Two forces F₁ and F₂ act on a particle P - Edexcel - A-Level Maths Mechanics - Question 7 - 2016 - Paper 1

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7. Two forces F₁ and F₂ act on a particle P. The force F₁ is given by F₁ = (-i + 2j) N and F₂ acts in the direction of the vector (i + j). Given that the resultant... show full transcript

Worked Solution & Example Answer:7. Two forces F₁ and F₂ act on a particle P - Edexcel - A-Level Maths Mechanics - Question 7 - 2016 - Paper 1

Step 1

(b) Find the speed of P when t = 3 seconds.

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Answer

To find the speed of particle P at t = 3 seconds, we use the kinematic equation relating initial velocity, acceleration, and time:

v=u+atv = u + at

Where:

  • u=(3i22j)u = (3i - 22j) m s⁻¹ (initial velocity)
  • a=(3i+9j)a = (3i + 9j) m s⁻² (acceleration)
  • t=3t = 3 seconds

Substituting the known values:

v=(3i22j)+(3i+9j)imes3v = (3i - 22j) + (3i + 9j) imes 3

Now calculate the acceleration term:

3i+9j3i + 9j

Expansion results in:

v=(3+3(3))i+(22+9(3))jv = (3 + 3(3))i + (-22 + 9(3))j

This leads to: v=(3+9)i+(22+27)jv = (3 + 9)i + (-22 + 27)j

To find the magnitude of the velocity vector:

v=(12)2+(5)2|v| = \sqrt{(12)^2 + (5)^2}

Calculating the magnitude:

v=144+25=169=13extm/s|v| = \sqrt{144 + 25} = \sqrt{169} = 13 ext{ m/s}

Therefore, the speed of P when t = 3 seconds is 13 m/s.

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