Photo AI

Figure 1 shows part of the curve with equation $y = e^{0.5x}$ - Edexcel - A-Level Maths Pure - Question 3 - 2008 - Paper 7

Question icon

Question 3

Figure-1-shows-part-of-the-curve-with-equation-$y-=-e^{0.5x}$-Edexcel-A-Level Maths Pure-Question 3-2008-Paper 7.png

Figure 1 shows part of the curve with equation $y = e^{0.5x}$. The finite region $R$, shown shaded in Figure 1, is bounded by the curve, the x-axis, the y-axis and t... show full transcript

Worked Solution & Example Answer:Figure 1 shows part of the curve with equation $y = e^{0.5x}$ - Edexcel - A-Level Maths Pure - Question 3 - 2008 - Paper 7

Step 1

Complete the table with the values of $y$ corresponding to $x = 0.8$ and $x = 1.6$

96%

114 rated

Answer

To find the values of yy for the given xx values:

  1. For x=0.8x = 0.8, we calculate:

    y=e0.5imes0.8=e0.41.4918y = e^{0.5 imes 0.8} = e^{0.4} \approx 1.4918 (rounded to 4 significant figures)

  2. For x=1.6x = 1.6, we calculate:

    y=e0.5imes1.6=e0.82.2255y = e^{0.5 imes 1.6} = e^{0.8} \approx 2.2255 (rounded to 4 significant figures)

Thus, the completed table will look like:

xx000.40.40.80.81.21.21.61.622
yye0e^{0}e0.4e^{0.4}1.49181.4918??2.22552.2255e2e^{2}

Step 2

Use the trapezium rule with all the values in the table to find an approximate value for the area of $R$

99%

104 rated

Answer

To calculate the area under the curve using the trapezium rule, we will use the formula:

extArea=12(b1+bn)+i=1n1bi ext{Area} = \frac{1}{2} (b_1 + b_n) + \sum_{i=1}^{n-1} b_i

where b1b_1 and bnb_n are the first and last ordinates and bib_i are the intermediate ordinates. The required values are:

  1. First ordinate (x=0x=0): y=e0=1y = e^{0} = 1
  2. Last ordinate (x=2x=2): y=e27.3891y = e^{2} \approx 7.3891
  3. Intermediate ordinates: e0.41.4918e^{0.4} \approx 1.4918, 1.49181.4918, 2.22552.2255

Now we calculate the area:

Area=12(1+7.3891)+(1.4918+1.4918+2.2255)\text{Area} = \frac{1}{2}(1 + 7.3891) + (1.4918 + 1.4918 + 2.2255)

Calculate: Area0.2×(1+2.2255+7.3891)\text{Area} \approx 0.2 \times (1 + 2.2255 + 7.3891)

Thus, summing gives:

Area4.922206\text{Area} \approx 4.922206

Rounding to 4 significant figures, the approximate area is 4.9224.922.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;