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A spherical mint of radius 5 mm is placed in the mouth and sucked - Edexcel - A-Level Maths Pure - Question 12 - 2018 - Paper 2

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A spherical mint of radius 5 mm is placed in the mouth and sucked. Four minutes later, the radius of the mint is 3 mm. In a simple model, the rate of decrease of th... show full transcript

Worked Solution & Example Answer:A spherical mint of radius 5 mm is placed in the mouth and sucked - Edexcel - A-Level Maths Pure - Question 12 - 2018 - Paper 2

Step 1

find an equation linking the radius of the mint and the time.

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Answer

Let ( r ) be the radius of the mint in mm and ( t ) be the time in minutes.

According to the problem, the rate of decrease of the radius is given by the relationship:

drdt=kr2\frac{dr}{dt} = -\frac{k}{r^2}

where ( k ) is a positive constant. By rearranging this equation, we can separate variables:

r2dr=kdtr^2 dr = -k dt

Now we will integrate both sides:

r2dr=kdt\int r^2 dr = -k \int dt

This results in:

r33=kt+c\frac{r^3}{3} = -kt + c

To determine the constant of integration ( c ), we apply the initial conditions when ( t = 0 ) and ( r = 5 ):

533=c    c=1253\frac{5^3}{3} = c \implies c = \frac{125}{3}

Now, substituting ( c ) back into the equation, we get:

r33=kt+1253\frac{r^3}{3} = -kt + \frac{125}{3}

Rearranging gives us the final equation:

r3=3kt+125r^3 = -3kt + 125

Step 2

Hence find the total time taken for the mint to completely dissolve.

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Answer

To find the total time taken for the mint to completely dissolve, we need to establish when ( r = 0 ).

Using the derived equation:

0=3kt+1250 = -3kt + 125

From the problem, after 4 minutes (( t = 4 )), the radius is 3 mm, so substituting ( r = 3 ) and ( t = 4 ):

33=3k(4)+125    27=12k+1253^3 = -3k(4) + 125 \implies 27 = -12k + 125

Solving for ( k ), we have:

12k=27125    12k=98    k=9812=4968.1667-12k = 27 - 125 \implies -12k = -98 \implies k = \frac{98}{12} = \frac{49}{6} \approx 8.1667

Now we shall substitute this value of ( k ) back into the equation to find total time:

0=3(496)t+125    3t75049    t51.43 minutes0 = -3(\frac{49}{6})t + 125 \implies 3t \approx \frac{750}{49} \implies t \approx 51.43 \text{ minutes}

Rounding to the nearest second:

Total time is approximately 51 minutes and 26 seconds.

Step 3

Suggest a limitation of the model.

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Answer

A suitable limitation of the model could be:

  • The model does not consider whether the mint is bitten.
  • It assumes a constant rate of dissolution, which might not be the case in reality.
  • The model does not account for variations in temperature or saliva production.
  • Potential changes in the shape of the mint are disregarded.
  • It does not incorporate the effect of time beyond certain limits, such as 5 minutes, where further behaviors may differ.

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