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Figure 1 shows part of the curve with equation $y = f(x)$, $x \in \mathbb{R}$ - Edexcel - A-Level Maths Pure - Question 25 - 2013 - Paper 1

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Figure 1 shows part of the curve with equation $y = f(x)$, $x \in \mathbb{R}$. The curve passes through the points $Q(0, 2)$ and $P(-3, 0)$ as shown. (a) Find t... show full transcript

Worked Solution & Example Answer:Figure 1 shows part of the curve with equation $y = f(x)$, $x \in \mathbb{R}$ - Edexcel - A-Level Maths Pure - Question 25 - 2013 - Paper 1

Step 1

Find the value of $f(-3)$

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Answer

Given that the curve passes through the point P(3,0)P(-3, 0), it follows that:

f(3)=0f(-3) = 0.

Thus, the function value is f(3)=0f(-3) = 0.

Step 2

Sketch the curve with equation $y = f^{-1}(x)$

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To sketch the inverse function y=f1(x)y = f^{-1}(x), we reflect the original function y=f(x)y = f(x) over the line y=xy = x. The critical points are approximately (0,2)(0, 2) and (2,0)(2, 0), leading to the points:

  • (2,0)(2, 0)
  • (0,2)(0, 2)

This indicates that the inverse graph increases from (3,0)(-3, 0) upwards, maintaining the shape of the original graph.

Step 3

Sketch the curve with equation $y = f(x) - 2$

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Answer

To sketch the curve y=f(x)2y = f(x) - 2, we take the original function and shift it down by 2 units. The key points will shift accordingly:

  • Original point Q(0,2)Q(0, 2) moves to (0,0)(0, 0).
  • Original point P(3,0)P(-3, 0) moves to (3,2)(-3, -2).

This transformation maintains the shape, illustrating a downward shift.

Step 4

Sketch the curve with equation $y = 2f(\frac{1}{2} x)$

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Answer

For the equation y=2f(12x)y = 2f(\frac{1}{2} x), we first horizontally stretch the graph by a factor of 2 and then vertically stretch by a factor of 2. The significant points change as follows:

  • The point (0,2)(0, 2) on the original curve will transform to (0,4)(0, 4).
  • The point (3,0)(-3, 0) will transform to (6,0)(-6, 0).

Sketching these will result in a more pronounced upward curve, with specific points reflecting the transformations.

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