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Given that $y = 2$ at $x = \frac{\pi}{4}$, solve the differential equation $$\frac{dy}{dx} = \frac{3}{y \cos x}$$ - Edexcel - A-Level Maths Pure - Question 6 - 2012 - Paper 7

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Given-that-$y-=-2$-at-$x-=-\frac{\pi}{4}$,-solve-the-differential-equation--$$\frac{dy}{dx}-=-\frac{3}{y-\cos-x}$$-Edexcel-A-Level Maths Pure-Question 6-2012-Paper 7.png

Given that $y = 2$ at $x = \frac{\pi}{4}$, solve the differential equation $$\frac{dy}{dx} = \frac{3}{y \cos x}$$

Worked Solution & Example Answer:Given that $y = 2$ at $x = \frac{\pi}{4}$, solve the differential equation $$\frac{dy}{dx} = \frac{3}{y \cos x}$$ - Edexcel - A-Level Maths Pure - Question 6 - 2012 - Paper 7

Step 1

Integrate both sides

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Answer

To solve the differential equation, we first rewrite it in a separable form:

ydy=3sec2xdxy \, dy = 3 \, sec^2 x \, dx

Now, we integrate both sides:

ydy=3sec2xdx\int y \, dy = \int 3 \, sec^2 x \, dx

This gives:

12y2=3tanx+C\frac{1}{2} y^2 = 3 \tan x + C

Step 2

Apply the initial condition $y = 2$ at $x = \frac{\pi}{4}$

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Answer

At x=π4x = \frac{\pi}{4}, y=2y = 2. We substitute these values into the equation:

12(2)2=3tan(π4)+C\frac{1}{2} (2)^2 = 3 \tan \left( \frac{\pi}{4} \right) + C

This simplifies to:

2=3(1)+C2 = 3(1) + C

Thus,

C=23=1C = 2 - 3 = -1

Step 3

Write the final solution

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Answer

Substituting back the value of CC into the integrated equation, we have:

12y2=3tanx1\frac{1}{2} y^2 = 3 \tan x - 1

To write this in a standard form:

y2=6tanx2y^2 = 6 \tan x - 2

This is the solution to the differential equation.

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