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12. (a) Show that the x coordinates of the turning points of the curve with equation y = f(x) satisfy the equation $\tan x = 4$ - Edexcel - A-Level Maths Pure - Question 14 - 2019 - Paper 1

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12. (a) Show that the x coordinates of the turning points of the curve with equation y = f(x) satisfy the equation $\tan x = 4$. (b) Sketch the graph of H against... show full transcript

Worked Solution & Example Answer:12. (a) Show that the x coordinates of the turning points of the curve with equation y = f(x) satisfy the equation $\tan x = 4$ - Edexcel - A-Level Maths Pure - Question 14 - 2019 - Paper 1

Step 1

Show that the x coordinates of the turning points of the curve with equation y = f(x) satisfy the equation tan x = 4.

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Answer

To find the turning points, we need to differentiate the given function:

f(x)=10e0.25xsinxf(x) = 10e^{-0.25x} \sin x

Differentiating using the product rule, we get:

f(x)=2.5e0.25xsinx+10e0.25xcosxf'(x) = -2.5e^{-0.25x} \sin x + 10e^{-0.25x} \cos x

Setting this equal to zero for critical points, we have:

2.5e0.25xsinx+10e0.25xcosx=0-2.5e^{-0.25x} \sin x + 10e^{-0.25x} \cos x = 0

This simplifies to:

tanx=102.5=4\tan x = \frac{10}{2.5} = 4

Thus, we have shown that the turning points satisfy the equation tanx=4\tan x = 4.

Step 2

Sketch the graph of H against t where H(t) = |10e^{-0.25t} sin x| showing the long-term behaviour of this curve.

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Answer

To sketch the graph of H against t:

  • Begin by noting that H(t)=10e0.25tsinxH(t) = |10e^{-0.25t} \sin x| will fluctuate between 0 and 10 as sinx\sin x oscillates between -1 and 1.
  • The factor e0.25te^{-0.25t} indicates that as t increases, the height will decay exponentially.
  • Therefore, we expect to see two peaks for each period of the sine wave, but the amplitude of the peaks will decrease over time.
  • The graph should show the height tapering off towards zero as t goes on.

Step 3

Find the maximum height of the ball above the ground between the first and second bounce.

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Answer

We can find the maximum height by substituting the value of xx that satisfies anx=4 an x = 4. Using a calculator, we find:

x1=arctan(4)1.3258(first turning point)x_1 = \arctan(4) \approx 1.3258 \quad (first\ turning\ point)

Substituting this into H, we get:

H(1.3258)=10e0.251.3258sin(1.3258)H(1.3258) = |10e^{-0.25 \cdot 1.3258} \sin(1.3258)|

Calculating gives:

10e0.33145sin(1.3258)3.18 metres\approx 10e^{-0.33145} \sin(1.3258) \approx 3.18 \text{ metres}

Thus, the maximum height is approximately 3.18 metres.

Step 4

Explain why this model should not be used to predict the time of each bounce.

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Answer

This model assumes that the conditions remain constant and does not take into account external factors such as air resistance or changes in the initial conditions of the ball's kick. Additionally, as the height decreases over time, the model fails to accurately predict the timings of subsequent bounces as they will become irregular and influenced by unforeseen variables.

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