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Simplify (a) $(2\sqrt{5})^2$ (b) \[ \frac{\sqrt{2}}{2\sqrt{5} - 3\sqrt{2}} \] giving your answer in the form $a + \sqrt{b}$, where $a$ and $b$ are integers. - Edexcel - A-Level Maths Pure - Question 3 - 2015 - Paper 1

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Simplify--(a)-$(2\sqrt{5})^2$----(b)-\[-\frac{\sqrt{2}}{2\sqrt{5}---3\sqrt{2}}-\]-giving-your-answer-in-the-form-$a-+-\sqrt{b}$,-where-$a$-and-$b$-are-integers.-Edexcel-A-Level Maths Pure-Question 3-2015-Paper 1.png

Simplify (a) $(2\sqrt{5})^2$ (b) \[ \frac{\sqrt{2}}{2\sqrt{5} - 3\sqrt{2}} \] giving your answer in the form $a + \sqrt{b}$, where $a$ and $b$ are integers.

Worked Solution & Example Answer:Simplify (a) $(2\sqrt{5})^2$ (b) \[ \frac{\sqrt{2}}{2\sqrt{5} - 3\sqrt{2}} \] giving your answer in the form $a + \sqrt{b}$, where $a$ and $b$ are integers. - Edexcel - A-Level Maths Pure - Question 3 - 2015 - Paper 1

Step 1

(a)

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Answer

To simplify (25)2(2\sqrt{5})^2, we apply the property of exponents:

(ab)2=a2b2(a \cdot b)^2 = a^2 \cdot b^2

Thus:

(25)2=22(5)2=45=20.(2\sqrt{5})^2 = 2^2 \cdot (\sqrt{5})^2 = 4 \cdot 5 = 20.

The simplified answer is 20.

Step 2

(b)

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104 rated

Answer

To simplify [ \frac{\sqrt{2}}{2\sqrt{5} - 3\sqrt{2}} ], we start by rationalizing the denominator.

Multiply the numerator and denominator by the conjugate of the denominator, which is 25+322\sqrt{5} + 3\sqrt{2}:

[ \frac{\sqrt{2}(2\sqrt{5} + 3\sqrt{2})}{(2\sqrt{5} - 3\sqrt{2})(2\sqrt{5} + 3\sqrt{2})} ]

Calculating the denominator:

(25)2(32)2=4592=2018=2.(2\sqrt{5})^2 - (3\sqrt{2})^2 = 4 \cdot 5 - 9 \cdot 2 = 20 - 18 = 2.

Now for the numerator:

2(25)+2(32)=210+32=210+6.\sqrt{2}(2\sqrt{5}) + \sqrt{2}(3\sqrt{2}) = 2\sqrt{10} + 3 \cdot 2 = 2\sqrt{10} + 6.

Combining these results, we get:

[ \frac{2\sqrt{10} + 6}{2}. ]

Now, divide each term in the numerator by 2:

[ \sqrt{10} + 3. ]

Thus, the final answer can be expressed as ( 3 + \sqrt{10} ), where a=3a = 3 and b=10b = 10.

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