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Figure 1 shows a sketch of the curve with equation $y = f(x)$ - Edexcel - A-Level Maths Pure - Question 8 - 2005 - Paper 2

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Question 8

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Figure 1 shows a sketch of the curve with equation $y = f(x)$. The curve crosses the x-axis at the points (2, 0) and (4, 0). The minimum point on the curve is $P(3, ... show full transcript

Worked Solution & Example Answer:Figure 1 shows a sketch of the curve with equation $y = f(x)$ - Edexcel - A-Level Maths Pure - Question 8 - 2005 - Paper 2

Step 1

Sketch the curve with equation $y = -f(x)$

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Answer

  1. Reflect the original curve in the x-axis. This means that all points (x,y)(x, y) on the original curve will change to (x,y)(x, -y).

  2. Identify the x-axis intersections from the original graph at points (2, 0) and (4, 0); these will remain the same for the reflected curve.

  3. Since the minimum point P(3,2)P(3, -2) on the original curve is reflected upwards, the new coordinates of this point will be P(3,2)P(3, 2).

  4. The final curve will intersect the x-axis at points (2, 0) and (4, 0), with the image of PP at (3, 2).

Step 2

Sketch the curve with equation $y = f(2x)$

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Answer

  1. This transformation represents a horizontal compression of the curve by a factor of 2. Each x-coordinate will be halved, meaning all points shift closer to the y-axis.

  2. For the x-axis crossings, the new points will be found by setting the original x-intercepts to half their values: (2, 0) becomes (1, 0) and (4, 0) becomes (2, 0).

  3. The minimum point P(3,2)P(3, -2) transforms to the new point P(1.5,2)P(1.5, -2).

  4. The new x-axis intercepts will be (1, 0) and (2, 0), with the image of PP at (1.5, -2).

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