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Find the first three terms, in ascending powers of x, of the binomial expansion of (3 + 2x)⁵, giving each term in its simplest form. - Edexcel - A-Level Maths Pure - Question 3 - 2005 - Paper 2

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Find the first three terms, in ascending powers of x, of the binomial expansion of (3 + 2x)⁵, giving each term in its simplest form.

Worked Solution & Example Answer:Find the first three terms, in ascending powers of x, of the binomial expansion of (3 + 2x)⁵, giving each term in its simplest form. - Edexcel - A-Level Maths Pure - Question 3 - 2005 - Paper 2

Step 1

Step 1: Identify the expansion terms

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Answer

The binomial expansion of (a + b)ⁿ can be expressed using the Binomial Theorem as:

(a+b)n=k=0n(nk)ankbk(a + b)^n = \sum_{k=0}^{n} {n \choose k} a^{n-k} b^k

For our case, a = 3, b = 2x, and n = 5.

Step 2

Step 2: Calculate the first three terms

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Answer

Using the Binomial Theorem:

  1. For k = 0:

(50)(3)5(2x)0=12431=243{5 \choose 0} (3)^{5} (2x)^{0} = 1 \cdot 243 \cdot 1 = 243

  1. For k = 1:

(51)(3)4(2x)1=581(2x)=810x{5 \choose 1} (3)^{4} (2x)^{1} = 5 \cdot 81 \cdot (2x) = 810x

  1. For k = 2:

(52)(3)3(2x)2=1027(4x2)=1080x2{5 \choose 2} (3)^{3} (2x)^{2} = 10 \cdot 27 \cdot (4x^2) = 1080x^2

Step 3

Step 3: Write the result

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Answer

Combining these terms, the first three terms of the binomial expansion are:

243+810x+1080x2243 + 810x + 1080x^2

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